Ranked #57 in Oxon Hill
Zalika Murray
Guide Score: 46%
Verified April 18, 2026
Zalika Murray brings professional real estate expertise to the Oxon Hill, MD community. Located at 6710 Oxon Hill Rd. Reach them at +12023688838. The Oxon Hill real estate market is competitive, and Zalika Murray has distinguished themselves through consistent quality and client satisfaction. Whether you are looking for a full-service real estate agent or specialized expertise, Zalika Murray offers solutions tailored to your specific requirements. Clients throughout the Oxon Hill metropolitan area rely on Zalika Murray for dependable real estate services that meet their unique needs and budget.
How We Scored Zalika Murray
- Google Rating
- N/A/5 → 0%
- Review Volume
- 0 reviews → 0%
- Credentials
- None listed → 0%
- Press Recognition
- 0 mentions → 0%
- Web Presence
- 45%
- Experience
- N/A → 0%
- Profile Completeness
- 47%
Key facts
- Based in
- Oxon Hill, MD
- Address
- 6710 Oxon Hill Rd
- Phone
- +12023688838
- zalika@homestrusted.com
Frequently asked questions
- What is Zalika Murray's ranking among real estate agents in Oxon Hill?
- Zalika Murray is ranked #57 in Oxon Hill with a Guide Score of 46%. This score is based on Google reviews, professional credentials, press recognition, and experience.
- What services does Zalika Murray specialize in?
- Zalika Murray's service specialties are not yet catalogued in our directory. Contact the agent directly for their current focus areas.
- What property types does Zalika Murray work with?
- Property type specialties for Zalika Murray are not yet listed. Contact the agent directly for details.
- Where is Zalika Murray based and what areas do they serve?
- Zalika Murray is based in Oxon Hill, MD. Their broader service area is not published; confirm with the agent before engaging for work outside the metro.
- How do I contact Zalika Murray?
- To contact Zalika Murray: call +12023688838, or email zalika@homestrusted.com. Most agents offer a free consultation to discuss your buying or selling needs.